{"id":65348,"date":"2026-09-14T04:45:43","date_gmt":"2026-09-14T08:45:43","guid":{"rendered":"https:\/\/www.wukongsch.com\/blog\/?p=65348"},"modified":"2026-09-14T04:45:45","modified_gmt":"2026-09-14T08:45:45","slug":"volume-of-a-hemisphere","status":"publish","type":"post","link":"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/","title":{"rendered":"Volume of a Hemisphere: Formula, Examples, and How to Find It"},"content":{"rendered":"<div style=\"margin-top: 0px; margin-bottom: 0px;\" class=\"sharethis-inline-share-buttons\" ><\/div>\n<p>The volume of a hemisphere is the amount of space inside half of a sphere. A hemisphere is created when a sphere is cut into two equal parts through its center. <\/p>\n\n\n\n<p>The <strong>volume of a hemisphere formula<\/strong> is <strong>V = 2\/3\u03c0r\u00b3<\/strong>, where <em>r<\/em> is the radius and \u03c0 is approximately 3.14. Because a hemisphere is exactly half of a sphere, its volume is also half of the sphere&#8217;s volume. <\/p>\n\n\n\n<p>In this guide, you will learn how to find the volume of a hemisphere, how to use radius and diameter, solve step-by-step examples, and avoid common mistakes involving units and formulas.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"how-to-find-the-volume-of-a-hemisphere\"><\/span>How to Find the Volume of a Hemisphere<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n\n<p>To find the <strong>volume of a hemisphere<\/strong>, you need to know its <strong>radius<\/strong>. Then use:<\/p>\n\n\n\n<p><strong>V = 2\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>The formula comes directly from the volume of a sphere:<\/p>\n\n\n\n<p><strong>Sphere: V = 4\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>A hemisphere is half of a sphere, so:<\/p>\n\n\n\n<p><strong>Hemisphere: V = 1\/2 \u00d7 4\/3\u03c0r\u00b3 = 2\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>This means you can find the volume by cubing the radius, multiplying by \u03c0 and 2, and then dividing by 3.<\/p>\n\n\n\n<p><strong>Try the interactive hemisphere explorer below.<\/strong> Move the slider to change the radius and see how the hemisphere&#8217;s volume changes.<\/p>\n\n\n\n<!-- Hemisphere Volume Explorer \u2014 paste into a WordPress Custom HTML block.\n     No <html>\/<head>\/<title>\/<meta> tags included. -->\n\n<div class=\"hemisphere-volume-explorer\" style=\"font-family:'Comic Sans MS','Segoe UI',-apple-system,Arial,sans-serif;max-width:680px;margin:0 auto;color:#0C447C;\">\n\n<style>\n  .hemisphere-volume-explorer {\n    background: linear-gradient(180deg, #F0F8FF 0%, #FFFFFF 100%);\n    border: 3px dashed #378ADD;\n    border-radius: 24px;\n    padding: 1.5rem 1.75rem 1.75rem;\n    box-sizing: border-box;\n  }\n\n  .hemisphere-volume-explorer * {\n    box-sizing: border-box;\n  }\n\n  .hemisphere-volume-explorer .hv-title {\n    font-size: 20px;\n    font-weight: 700;\n    text-align: center;\n    margin: 0 0 0.35rem;\n    color: #0C447C;\n  }\n\n  .hemisphere-volume-explorer .hv-subtitle {\n    font-size: 14px;\n    text-align: center;\n    color: #185FA5;\n    margin: 0 0 1.2rem;\n  }\n\n  .hemisphere-volume-explorer .hv-wrap {\n    display: grid;\n    grid-template-columns: 1fr 1fr;\n    gap: 1.5rem;\n    align-items: center;\n  }\n\n  @media (max-width: 560px) {\n    .hemisphere-volume-explorer .hv-wrap {\n      grid-template-columns: 1fr;\n    }\n  }\n\n  .hemisphere-volume-explorer .hv-frame {\n    background: #FFFFFF;\n    border: 2px solid #85B7EB;\n    border-radius: 18px;\n    padding: 0.5rem;\n  }\n\n  .hemisphere-volume-explorer .hv-slider-row {\n    margin-bottom: 1.1rem;\n  }\n\n  .hemisphere-volume-explorer .hv-slider-label {\n    display: flex;\n    justify-content: space-between;\n    align-items: center;\n    font-size: 14px;\n    font-weight: 600;\n    color: #185FA5;\n    margin-bottom: 6px;\n  }\n\n  .hemisphere-volume-explorer .hv-pill {\n    background: #B5D4F4;\n    color: #0C447C;\n    padding: 2px 10px;\n    border-radius: 999px;\n    font-weight: 700;\n    min-width: 35px;\n    text-align: center;\n  }\n\n  .hemisphere-volume-explorer input[type=\"range\"] {\n    width: 100%;\n    height: 8px;\n    border-radius: 999px;\n    background: #B5D4F4;\n    -webkit-appearance: none;\n    appearance: none;\n    outline: none;\n    cursor: pointer;\n  }\n\n  .hemisphere-volume-explorer input[type=\"range\"]::-webkit-slider-thumb {\n    -webkit-appearance: none;\n    appearance: none;\n    width: 22px;\n    height: 22px;\n    border-radius: 50%;\n    background: #378ADD;\n    border: 3px solid #FFFFFF;\n    box-shadow: 0 0 0 2px #378ADD;\n    cursor: pointer;\n  }\n\n  .hemisphere-volume-explorer input[type=\"range\"]::-moz-range-thumb {\n    width: 22px;\n    height: 22px;\n    border-radius: 50%;\n    background: #378ADD;\n    border: 3px solid #FFFFFF;\n    box-shadow: 0 0 0 2px #378ADD;\n    cursor: pointer;\n  }\n\n  .hemisphere-volume-explorer .hv-result-box {\n    background: #E6F1FB;\n    border: 2px dashed #185FA5;\n    border-radius: 16px;\n    padding: 1rem;\n    text-align: center;\n    margin-top: 0.8rem;\n  }\n\n  .hemisphere-volume-explorer .hv-result-label {\n    font-size: 13px;\n    font-weight: 600;\n    color: #185FA5;\n    margin-bottom: 4px;\n  }\n\n  .hemisphere-volume-explorer .hv-value {\n    font-size: 16px;\n    color: #0C447C;\n    margin: 5px 0;\n  }\n\n  .hemisphere-volume-explorer .hv-main-result {\n    font-size: 25px;\n    font-weight: 800;\n    color: #042C53;\n    margin-top: 8px;\n  }\n\n  .hemisphere-volume-explorer .hv-note {\n    font-size: 13px;\n    text-align: center;\n    color: #185FA5;\n    margin-top: 12px;\n    line-height: 1.5;\n  }\n\n  .hemisphere-volume-explorer svg {\n    width: 100%;\n    height: auto;\n    display: block;\n  }\n<\/style>\n\n<p class=\"hv-title\">Build a Hemisphere and Find Its Volume!<\/p>\n\n<p class=\"hv-subtitle\">\n  Move the slider to change the radius.\n<\/p>\n\n<div class=\"hv-wrap\">\n\n  <!-- Hemisphere illustration -->\n  <div class=\"hv-frame\">\n\n    <svg id=\"hv-svg\" viewBox=\"0 0 300 300\" aria-label=\"Interactive hemisphere showing radius and diameter\">\n\n      <!-- Hemisphere dome -->\n      <path\n        id=\"hv-dome\"\n        d=\"M 70 155 A 80 80 0 0 1 230 155 Z\"\n        fill=\"#E6F1FB\"\n        stroke=\"#0C447C\"\n        stroke-width=\"3\"\n      \/>\n\n      <!-- Flat circular base -->\n      <ellipse\n        id=\"hv-base\"\n        cx=\"150\"\n        cy=\"155\"\n        rx=\"80\"\n        ry=\"22\"\n        fill=\"#B5D4F4\"\n        stroke=\"#0C447C\"\n        stroke-width=\"3\"\n      \/>\n\n      <!-- Radius line -->\n      <line\n        id=\"hv-radius-line\"\n        x1=\"150\"\n        y1=\"155\"\n        x2=\"230\"\n        y2=\"155\"\n        stroke=\"#378ADD\"\n        stroke-width=\"4\"\n      \/>\n\n      <!-- Diameter line -->\n      <line\n        id=\"hv-diameter-line\"\n        x1=\"70\"\n        y1=\"155\"\n        x2=\"230\"\n        y2=\"155\"\n        stroke=\"#185FA5\"\n        stroke-width=\"3\"\n        stroke-dasharray=\"7 5\"\n      \/>\n\n      <!-- Center point -->\n      <circle\n        cx=\"150\"\n        cy=\"155\"\n        r=\"5\"\n        fill=\"#0C447C\"\n      \/>\n\n      <!-- Radius label -->\n      <text\n        id=\"hv-radius-label\"\n        x=\"190\"\n        y=\"145\"\n        text-anchor=\"middle\"\n        font-size=\"14\"\n        font-weight=\"700\"\n        fill=\"#042C53\">\n        r = 5\n      <\/text>\n\n      <!-- Diameter label -->\n      <text\n        id=\"hv-diameter-label\"\n        x=\"150\"\n        y=\"190\"\n        text-anchor=\"middle\"\n        font-size=\"14\"\n        font-weight=\"700\"\n        fill=\"#185FA5\">\n        d = 10\n      <\/text>\n\n      <!-- Shape label -->\n      <text\n        x=\"150\"\n        y=\"270\"\n        text-anchor=\"middle\"\n        font-size=\"13\"\n        font-weight=\"700\"\n        fill=\"#185FA5\">\n        Hemisphere = \u00bd of a sphere\n      <\/text>\n\n    <\/svg>\n\n  <\/div>\n\n  <!-- Controls -->\n  <div>\n\n    <div class=\"hv-slider-row\">\n\n      <div class=\"hv-slider-label\">\n        <span>Radius (r)<\/span>\n        <span class=\"hv-pill\" id=\"hv-r-out\">5<\/span>\n      <\/div>\n\n      <input\n        type=\"range\"\n        id=\"hv-r\"\n        min=\"2\"\n        max=\"10\"\n        value=\"5\"\n        step=\"1\"\n        aria-label=\"Hemisphere radius\"\n      \/>\n\n    <\/div>\n\n    <div class=\"hv-result-box\">\n\n      <div class=\"hv-result-label\">\n        Hemisphere Measurements\n      <\/div>\n\n      <div class=\"hv-value\" id=\"hv-d-out\">\n        Diameter: 10 cm\n      <\/div>\n\n      <div class=\"hv-value\">\n        V = 2\/3 &times; &pi; &times; r&sup3;\n      <\/div>\n\n      <div class=\"hv-value\" id=\"hv-formula-out\">\n        V = 2\/3 &times; &pi; &times; 5&sup3;\n      <\/div>\n\n      <div class=\"hv-main-result\" id=\"hv-volume-out\">\n        &asymp; 261.80 cm&sup3;\n      <\/div>\n\n    <\/div>\n\n    <div class=\"hv-note\">\n      A hemisphere has half the volume of a sphere\n      with the same radius.\n    <\/div>\n\n  <\/div>\n\n<\/div>\n\n<script>\n(function() {\n\n  const rEl = document.getElementById('hv-r');\n\n  const dome = document.getElementById('hv-dome');\n  const base = document.getElementById('hv-base');\n\n  const radiusLine = document.getElementById('hv-radius-line');\n  const diameterLine = document.getElementById('hv-diameter-line');\n\n  const rOut = document.getElementById('hv-r-out');\n  const dOut = document.getElementById('hv-d-out');\n\n  const formulaOut = document.getElementById('hv-formula-out');\n  const volumeOut = document.getElementById('hv-volume-out');\n\n  const radiusLabel = document.getElementById('hv-radius-label');\n  const diameterLabel = document.getElementById('hv-diameter-label');\n\n  const cx = 150;\n  const baseY = 155;\n\n  const visualScale = 13;\n\n  function updateHemisphere() {\n\n    const r = parseInt(\n      rEl.value,\n      10\n    );\n\n    const d = r * 2;\n\n    const volume =\n      (2 \/ 3) *\n      Math.PI *\n      Math.pow(r, 3);\n\n    const visualRadius =\n      r * visualScale;\n\n    const left =\n      cx - visualRadius;\n\n    const right =\n      cx + visualRadius;\n\n    \/*\n      Update hemisphere dome.\n    *\/\n\n    dome.setAttribute(\n      'd',\n      'M ' +\n      left +\n      ' ' +\n      baseY +\n      ' A ' +\n      visualRadius +\n      ' ' +\n      visualRadius +\n      ' 0 0 1 ' +\n      right +\n      ' ' +\n      baseY +\n      ' Z'\n    );\n\n    \/*\n      Update flat base.\n    *\/\n\n    base.setAttribute(\n      'cx',\n      cx\n    );\n\n    base.setAttribute(\n      'cy',\n      baseY\n    );\n\n    base.setAttribute(\n      'rx',\n      visualRadius\n    );\n\n    \/*\n      Update radius line.\n    *\/\n\n    radiusLine.setAttribute(\n      'x1',\n      cx\n    );\n\n    radiusLine.setAttribute(\n      'x2',\n      right\n    );\n\n    radiusLine.setAttribute(\n      'y1',\n      baseY\n    );\n\n    radiusLine.setAttribute(\n      'y2',\n      baseY\n    );\n\n    \/*\n      Update diameter line.\n    *\/\n\n    diameterLine.setAttribute(\n      'x1',\n      left\n    );\n\n    diameterLine.setAttribute(\n      'x2',\n      right\n    );\n\n    diameterLine.setAttribute(\n      'y1',\n      baseY\n    );\n\n    diameterLine.setAttribute(\n      'y2',\n      baseY\n    );\n\n    \/*\n      Update labels.\n    *\/\n\n    radiusLabel.setAttribute(\n      'x',\n      cx + visualRadius \/ 2\n    );\n\n    radiusLabel.setAttribute(\n      'y',\n      baseY - 10\n    );\n\n    radiusLabel.textContent =\n      'r = ' + r;\n\n    diameterLabel.textContent =\n      'd = ' + d;\n\n    \/*\n      Update results.\n    *\/\n\n    rOut.textContent = r;\n\n    dOut.textContent =\n      'Diameter: ' +\n      d +\n      ' cm';\n\n    formulaOut.innerHTML =\n      'V = 2\/3 &times; &pi; &times; ' +\n      r +\n      '&sup3;';\n\n    volumeOut.innerHTML =\n      '&asymp; ' +\n      volume.toFixed(2) +\n      ' cm&sup3;';\n\n  }\n\n  rEl.addEventListener(\n    'input',\n    updateHemisphere\n  );\n\n  updateHemisphere();\n\n})();\n<\/script>\n\n<\/div>\n\n\n\n<p>The interactive model makes one important idea easy to see: as the radius increases, the volume increases much faster, because the radius is <strong>cubed<\/strong> in the formula.<\/p>\n\n\n\n<p>For example, doubling the radius does not simply double the volume. It makes the volume <strong>8 times larger<\/strong>, because:<\/p>\n\n\n\n<p><strong>(2r)\u00b3 = 8r\u00b3<\/strong><\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"what-is-the-volume-of-a-hemisphere\"><\/span>What Is the Volume of a Hemisphere?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n\n<p>The volume of a hemisphere is the amount of three-dimensional space contained inside a hemisphere.<\/p>\n\n\n\n<p>A hemisphere is exactly <strong>half of a sphere<\/strong>. The word \u201chemi\u201d means half. If you cut a sphere through its center, you create two equal hemispheres.<\/p>\n\n\n\n<p>A hemisphere has:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>One curved surface<\/li>\n\n\n\n<li>One flat circular base<\/li>\n\n\n\n<li>A radius extending from the center of the original sphere to the curved surface<\/li>\n\n\n\n<li>A diameter across the circular base<\/li>\n<\/ul>\n\n\n\n<p>The volume measures the space inside the shape. It is different from the surface area, which measures the outside surfaces.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Hemisphere vs. Sphere<\/h3>\n\n\n\n<p>The easiest way to understand hemisphere volume is to compare it with sphere volume.<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><tbody><tr><th>Shape<\/th><th>Volume Formula<\/th><th>Relationship<\/th><\/tr><tr><td>Sphere<\/td><td>V = 4\/3\u03c0r\u00b3<\/td><td>Full sphere<\/td><\/tr><tr><td>Hemisphere<\/td><td>V = 2\/3\u03c0r\u00b3<\/td><td>Half of a sphere<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p>If two identical hemispheres are put together along their flat circular bases, they form one complete sphere. Therefore, two identical hemispheres have the same total volume as one sphere.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Volume vs. Surface Area<\/h3>\n\n\n\n<p>Do not confuse the volume of a hemisphere with its surface area.<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><tbody><tr><th>Measurement<\/th><th>What It Measures<\/th><th>Formula<\/th><\/tr><tr><td>Volume<\/td><td>Space inside the hemisphere<\/td><td>V = 2\/3\u03c0r\u00b3<\/td><\/tr><tr><td>Curved Surface Area<\/td><td>Curved outside surface<\/td><td>2\u03c0r\u00b2<\/td><\/tr><tr><td>Total Surface Area<\/td><td>Curved surface + flat base<\/td><td>3\u03c0r\u00b2<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p>The formulas are different because volume measures three-dimensional space, while surface area measures two-dimensional surfaces.<\/p>\n\n\n\n<p>For volume, the radius is cubed. Therefore, the answer must be written in <strong>cubic units<\/strong>, such as cm\u00b3, m\u00b3, or in\u00b3.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"volume-of-a-hemisphere-formula\"><\/span>Volume of a Hemisphere Formula<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n\n<p>The standard volume of a hemisphere formula is:<\/p>\n\n\n\n<p><strong>V = 2\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>V<\/strong> = volume of the hemisphere<\/li>\n\n\n\n<li><strong>\u03c0<\/strong> = pi, approximately 3.14<\/li>\n\n\n\n<li><strong>r<\/strong> = radius of the hemisphere<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Why Is the Formula 2\/3\u03c0r\u00b3?<\/h3>\n\n\n\n<p>Start with the formula for a sphere:<\/p>\n\n\n\n<p><strong>V = 4\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>A hemisphere is exactly half of a sphere, so divide the sphere&#8217;s volume by 2:<\/p>\n\n\n\n<p><strong>V = 1\/2 \u00d7 4\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>Therefore:<\/p>\n\n\n\n<p><strong>V = 2\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>This is why the coefficient in the hemisphere formula is <strong>2\/3<\/strong>, rather than <strong>4\/3<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">What If the Diameter Is Given?<\/h3>\n\n\n\n<p>Sometimes a problem gives you the <strong>diameter<\/strong> instead of the radius.<\/p>\n\n\n\n<p>Remember:<\/p>\n\n\n\n<p><strong>d = 2r<\/strong><\/p>\n\n\n\n<p>Therefore:<\/p>\n\n\n\n<p><strong>r = d\/2<\/strong><\/p>\n\n\n\n<p>If the diameter is 12 cm, the radius is:<\/p>\n\n\n\n<p><strong>r = 12 \u00f7 2 = 6 cm<\/strong><\/p>\n\n\n\n<p>Then use the standard formula:<\/p>\n\n\n\n<p><strong>V = 2\/3\u03c0(6)\u00b3<\/strong><\/p>\n\n\n\n<p>You should always convert diameter to radius before using <strong>V = 2\/3\u03c0r\u00b3<\/strong>.<\/p>\n\n\n\n<p>You can also write the hemisphere volume directly in terms of diameter:<\/p>\n\n\n\n<p><strong>V = 1\/12\u03c0d\u00b3<\/strong><\/p>\n\n\n\n<p>However, for most students, converting the diameter to radius first is easier and helps avoid mistakes.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"how-to-find-the-volume-of-a-hemisphere-2\"><\/span>How to Find the Volume of a Hemisphere<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n\n<p>You can find the volume of a hemisphere in three simple steps.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Find the Radius<\/h3>\n\n\n\n<p>Look at the information given in the problem.<\/p>\n\n\n\n<p>If the radius is given, use it directly.<\/p>\n\n\n\n<p>If the diameter is given, divide it by 2:<\/p>\n\n\n\n<p><strong>r = d \u00f7 2<\/strong><\/p>\n\n\n\n<p>For example, if:<\/p>\n\n\n\n<p><strong>d = 14 cm<\/strong><\/p>\n\n\n\n<p>then:<\/p>\n\n\n\n<p><strong>r = 14 \u00f7 2 = 7 cm<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Use the Hemisphere Volume Formula<\/h3>\n\n\n\n<p>Write:<\/p>\n\n\n\n<p><strong>V = 2\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>Then substitute the radius.<\/p>\n\n\n\n<p>For r = 7 cm:<\/p>\n\n\n\n<p><strong>V = 2\/3\u03c0(7)\u00b3<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Calculate the Volume<\/h3>\n\n\n\n<p>First cube the radius:<\/p>\n\n\n\n<p><strong>7\u00b3 = 343<\/strong><\/p>\n\n\n\n<p>Then:<\/p>\n\n\n\n<p><strong>V = 2\/3 \u00d7 \u03c0 \u00d7 343<\/strong><\/p>\n\n\n\n<p>Using \u03c0 \u2248 3.14:<\/p>\n\n\n\n<p><strong>V \u2248 718.38 cm\u00b3<\/strong><\/p>\n\n\n\n<p>So the volume of the hemisphere is approximately:<\/p>\n\n\n\n<p><strong>718.38 cm\u00b3<\/strong><\/p>\n\n\n\n<p>Always use cubic units for volume.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Quick Formula Guide<\/h3>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><tbody><tr><th>Given Information<\/th><th>Formula or Step<\/th><th>What to Do<\/th><\/tr><tr><td>Radius<\/td><td>V = 2\/3\u03c0r\u00b3<\/td><td>Substitute the radius<\/td><\/tr><tr><td>Diameter<\/td><td>r = d \u00f7 2<\/td><td>Find the radius first<\/td><\/tr><tr><td>Diameter directly<\/td><td>V = 1\/12\u03c0d\u00b3<\/td><td>Substitute the diameter<\/td><\/tr><tr><td>Sphere volume<\/td><td>V = 4\/3\u03c0r\u00b3<\/td><td>Divide by 2 for a hemisphere<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"volume-of-a-hemisphere-worked-examples\"><\/span>Volume of a Hemisphere: Worked Examples<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\">Example 1: Find the Volume From the Radius<\/h3>\n\n\n\n<p><strong>Problem:<\/strong> Find the volume of a hemisphere with a radius of 5 cm. Use \u03c0 \u2248 3.14.<\/p>\n\n\n\n<p><strong>Step 1: Write the formula.<\/strong><\/p>\n\n\n\n<p>V = 2\/3\u03c0r\u00b3<\/p>\n\n\n\n<p><strong>Step 2: Substitute r = 5.<\/strong><\/p>\n\n\n\n<p>V = 2\/3 \u00d7 3.14 \u00d7 5\u00b3<\/p>\n\n\n\n<p><strong>Step 3: Cube the radius.<\/strong><\/p>\n\n\n\n<p>5\u00b3 = 125<\/p>\n\n\n\n<p>So:<\/p>\n\n\n\n<p>V = 2\/3 \u00d7 3.14 \u00d7 125<\/p>\n\n\n\n<p>V \u2248 261.67 cm\u00b3<\/p>\n\n\n\n<p><strong>Answer: 261.67 cm\u00b3<\/strong><\/p>\n\n\n\n<p>The volume of the hemisphere is approximately <strong>261.67 cubic centimeters<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Example 2: Find the Volume From the Diameter<\/h3>\n\n\n\n<p><strong>Problem:<\/strong> A hemisphere has a diameter of 12 cm. What is its volume?<\/p>\n\n\n\n<p>The formula requires the radius, so first find the radius.<\/p>\n\n\n\n<p><strong>r = d \u00f7 2<\/strong><\/p>\n\n\n\n<p><strong>r = 12 \u00f7 2 = 6 cm<\/strong><\/p>\n\n\n\n<p>Now use:<\/p>\n\n\n\n<p><strong>V = 2\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>Substitute:<\/p>\n\n\n\n<p><strong>V = 2\/3 \u00d7 3.14 \u00d7 6\u00b3<\/strong><\/p>\n\n\n\n<p>Since:<\/p>\n\n\n\n<p><strong>6\u00b3 = 216<\/strong><\/p>\n\n\n\n<p>we get:<\/p>\n\n\n\n<p><strong>V = 2\/3 \u00d7 3.14 \u00d7 216<\/strong><\/p>\n\n\n\n<p><strong>V \u2248 452.16 cm\u00b3<\/strong><\/p>\n\n\n\n<p><strong>Answer: 452.16 cm\u00b3<\/strong><\/p>\n\n\n\n<p>This is a common type of hemisphere problem. The most important step is remembering to divide the diameter by 2 before using the radius-based formula.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Example 3: Compare a Sphere and a Hemisphere<\/h3>\n\n\n\n<p><strong>Problem:<\/strong> A sphere and a hemisphere have the same radius of 6 inches. How much larger is the sphere&#8217;s volume?<\/p>\n\n\n\n<p>Sphere:<\/p>\n\n\n\n<p><strong>V = 4\/3\u03c0(6)\u00b3<\/strong><\/p>\n\n\n\n<p>Hemisphere:<\/p>\n\n\n\n<p><strong>V = 2\/3\u03c0(6)\u00b3<\/strong><\/p>\n\n\n\n<p>Because the hemisphere is exactly half of the sphere:<\/p>\n\n\n\n<p><strong>Sphere volume = 2 \u00d7 hemisphere volume<\/strong><\/p>\n\n\n\n<p>Using \u03c0 \u2248 3.14:<\/p>\n\n\n\n<p>Sphere:<\/p>\n\n\n\n<p><strong>V \u2248 904.32 in\u00b3<\/strong><\/p>\n\n\n\n<p>Hemisphere:<\/p>\n\n\n\n<p><strong>V \u2248 452.16 in\u00b3<\/strong><\/p>\n\n\n\n<p>Therefore, the sphere has twice the volume of the hemisphere.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Example 4: A Real-World Hemisphere<\/h3>\n\n\n\n<p>Imagine a bowl shaped like a hemisphere with a radius of 10 cm. How much space can it hold?<\/p>\n\n\n\n<p>Use:<\/p>\n\n\n\n<p><strong>V = 2\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>Substitute:<\/p>\n\n\n\n<p><strong>V = 2\/3 \u00d7 3.14 \u00d7 10\u00b3<\/strong><\/p>\n\n\n\n<p>Since:<\/p>\n\n\n\n<p><strong>10\u00b3 = 1,000<\/strong><\/p>\n\n\n\n<p>we get:<\/p>\n\n\n\n<p><strong>V \u2248 2,093.33 cm\u00b3<\/strong><\/p>\n\n\n\n<p>Therefore, the bowl can hold approximately <strong>2,093.33 cubic centimeters<\/strong> of space, assuming it is a perfect hemisphere.<\/p>\n\n\n\n<p>Hemisphere volume can be useful for estimating the capacity of bowls, domes, tanks, and other objects with a half-sphere shape.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"common-mistakes-when-finding-the-volume-of-a-hemisphere\"><\/span>Common Mistakes When Finding the Volume of a Hemisphere<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\">1. Using the Sphere Formula<\/h3>\n\n\n\n<p>A common mistake is using:<\/p>\n\n\n\n<p><strong>V = 4\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>for a hemisphere.<\/p>\n\n\n\n<p>That formula gives the volume of a <strong>full sphere<\/strong>.<\/p>\n\n\n\n<p>For a hemisphere, use:<\/p>\n\n\n\n<p><strong>V = 2\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>A simple way to remember this is:<\/p>\n\n\n\n<p><strong>Hemisphere = half of a sphere<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">2. Forgetting to Convert Diameter to Radius<\/h3>\n\n\n\n<p>If a problem gives the diameter, do not substitute it directly for r.<\/p>\n\n\n\n<p>For example, if:<\/p>\n\n\n\n<p><strong>d = 10 cm<\/strong><\/p>\n\n\n\n<p>then:<\/p>\n\n\n\n<p><strong>r = 5 cm<\/strong><\/p>\n\n\n\n<p>Using 10 instead of 5 in the formula would produce a much larger answer because the radius is cubed.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">3. Forgetting to Cube the Radius<\/h3>\n\n\n\n<p>The formula is:<\/p>\n\n\n\n<p><strong>V = 2\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>not:<\/p>\n\n\n\n<p><strong>V = 2\/3\u03c0r<\/strong><\/p>\n\n\n\n<p>You need to calculate:<\/p>\n\n\n\n<p><strong>r \u00d7 r \u00d7 r<\/strong><\/p>\n\n\n\n<p>before completing the calculation.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">4. Confusing Volume and Surface Area<\/h3>\n\n\n\n<p>Volume uses:<\/p>\n\n\n\n<p><strong>V = 2\/3\u03c0r\u00b3<\/strong><\/p>\n\n\n\n<p>Surface area uses a different formula.<\/p>\n\n\n\n<p>For example, the total surface area of a hemisphere is:<\/p>\n\n\n\n<p><strong>A = 3\u03c0r\u00b2<\/strong><\/p>\n\n\n\n<p>Do not use a surface-area formula when the question asks for volume.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">5. Using the Wrong Units<\/h3>\n\n\n\n<p>Volume is measured in <strong>cubic units<\/strong>.<\/p>\n\n\n\n<p>Correct:<\/p>\n\n\n\n<p><strong>452.16 cm\u00b3<\/strong><\/p>\n\n\n\n<p>Incorrect:<\/p>\n\n\n\n<p><strong>452.16 cm\u00b2<\/strong><\/p>\n\n\n\n<p>The exponent 3 is important because volume measures three-dimensional space.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"faq\"><\/span>FAQ<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n\n<h3 class=\"wp-block-heading\">1. What is the formula for the volume of a hemisphere?<\/h3>\n\n\n\n<p>The formula is <strong>V = 2\/3\u03c0r\u00b3<\/strong>, where r is the radius. It is exactly half of the volume of a sphere with the same radius.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">2. How do you find the volume of a hemisphere?<\/h3>\n\n\n\n<p>Find the radius, cube it, multiply by \u03c0 and 2, and divide by 3. In formula form: <strong>V = 2\/3\u03c0r\u00b3<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">3. How do you find the volume of a hemisphere when the diameter is given?<\/h3>\n\n\n\n<p>First divide the diameter by 2 to find the radius. Then substitute the radius into <strong>V = 2\/3\u03c0r\u00b3<\/strong>. For example, a diameter of 12 cm gives a radius of 6 cm.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">4. Is the volume of a hemisphere half the volume of a sphere?<\/h3>\n\n\n\n<p>Yes. A hemisphere is exactly half of a sphere when the sphere is divided through its center. Therefore, its volume is half of the sphere&#8217;s volume.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">5. What is the difference between a sphere and a hemisphere?<\/h3>\n\n\n\n<p>A sphere is a complete three-dimensional round shape. A hemisphere is exactly half of a sphere, and has a curved surface plus a flat circular base. The volume of a hemisphere is half the volume of a sphere with the same radius.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"conclusion\"><\/span>Conclusion<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n\n<p>The volume of a hemisphere measures the space inside half of a sphere. The key formula to remember is <strong>V = 2\/3\u03c0r\u00b3<\/strong>. If the radius is given, substitute it directly into the formula. If the diameter is given, divide it by 2 first to find the radius. Because volume is three-dimensional, the final answer should always use cubic units.<\/p>\n\n\n\n<p>The most important idea is that a hemisphere is <strong>exactly half of a sphere<\/strong>. Once you understand the sphere formula <strong>4\/3\u03c0r\u00b3<\/strong>, the hemisphere formula <strong>2\/3\u03c0r\u00b3<\/strong> becomes much easier to remember and apply. <\/p>\n\n\n\n<p>For students who want more guided practice with geometry, formulas, and problem-solving, <a href=\"https:\/\/www.wukongsch.com\/\">WuKong Education<\/a> provides <a href=\"https:\/\/www.wukongsch.com\/learn-math\/\">structured online math class for kids<\/a>, with practices for different grade levels.<\/p>\n<div class=\"retention-card-new\" data-lang=\"en\" data-subject=\"CHINESE\" data-btnName=\"Get started free!\" data-subTitle=\"Specially tailored for kids aged 3-18 around the world!\">\r\n    <div class=\"retention-card-l\">\r\n        <div class=\"trustpilot-image\">\r\n            <!-- TrustBox widget - Micro Star -->\r\n            <div class=\"trustpilot-widget\" data-locale=\"en-US\" data-template-id=\"5419b732fbfb950b10de65e5\" data-businessunit-id=\"60c847b7f033d300019ff3a1\" data-style-height=\"24px\" data-style-width=\"272px\" data-token=\"7dc9fdab-8926-4826-ad90-81ab38cc0953\">\r\n              <a href=\"https:\/\/www.trustpilot.com\/review\/wukongsch.com\" target=\"_blank\" rel=\"noopener\">Trustpilot<\/a>\r\n            <\/div>\r\n            <!-- End TrustBox widget -->\r\n        <\/div>\r\n        <h3><p>Learn <span>authentic Chinese<\/span> from those who live and breathe the culture.<\/p>\n<\/h3>\r\n        <p>Specially tailored for kids aged 3-18 around the world!<\/p>\r\n        <a class=\"retention-card-button is-point\" href=\"https:\/\/www.wukongsch.com\/independent-appointment\/?subject=chinese&amp;l=d232a08b-51de-4a90-b301-47ad0f87f71a&amp;booking_triggerevent=BLOG_DETAIL_MODEL_CTA_BUTTON\" data-buttonname=\"\u7acb\u5373\u9884\u7ea6\u6309\u94ae\u70b9\u51fb\" data-event=\"C_Blog_BLOG_DETAIL_MIDDLE_CTA_BUTTON\" data-expose-buttonname=\"\u7acb\u5373\u9884\u7ea6\u6309\u94ae\u66dd\u5149\" data-expose-event=\"D_Blog_BLOG_DETAIL_MIDDLE_CTA_BUTTON\" target=\"_blank\" title=\"Get started free!\">\r\n            Get started free!\r\n        <\/a>\r\n    <\/div>\r\n    <div class=\"retention-card-r\"><\/div>\r\n<\/div>","protected":false},"excerpt":{"rendered":"<p>The volume of a hemisphere is the amount of space inside half of a sphere. A hemisphere is created when a sphere is cut into two equal parts through its center. The volume of a hemisphere formula is V = 2\/3\u03c0r\u00b3, where r is the radius and \u03c0 is approximately 3.14. Because a hemisphere is exactly half of a sphere, its volume is also half of the sphere&#8217;s volume. In this guide, you will learn how to find the volume of a hemisphere, how to use radius and diameter, solve step-by-step examples, and avoid common mistakes involving units and formulas. How to Find the Volume of a Hemisphere To find the volume of a hemisphere, you need to know its&#46;&#46;&#46;<\/p>\n","protected":false},"author":211806805,"featured_media":65350,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"_coblocks_attr":"","_coblocks_dimensions":"","_coblocks_responsive_height":"","_coblocks_accordion_ie_support":"","footnotes":""},"categories":[134689],"tags":[],"class_list":["post-65348","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-math-learning"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v22.7 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Volume of a Hemisphere: Formula, Examples, and How to Find It - WuKong Education<\/title>\n<meta name=\"description\" content=\"Learn how to find the volume of a hemisphere using the formula V = 2\/3\u03c0r\u00b3. Explore radius and diameter examples, step-by-step solutions, common mistakes, and practice tips.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Volume of a Hemisphere: Formula, Examples, and How to Find It - WuKong Education\" \/>\n<meta property=\"og:description\" content=\"Learn how to find the volume of a hemisphere using the formula V = 2\/3\u03c0r\u00b3. Explore radius and diameter examples, step-by-step solutions, common mistakes, and practice tips.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/\" \/>\n<meta property=\"og:site_name\" content=\"WuKong Education\" \/>\n<meta property=\"article:published_time\" content=\"2026-09-14T08:45:43+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2026-09-14T08:45:45+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/wp-more.wukongedu.net\/blog\/wp-content\/uploads\/2026\/09\/1-5.webp\" \/>\n\t<meta property=\"og:image:width\" content=\"824\" \/>\n\t<meta property=\"og:image:height\" content=\"431\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/webp\" \/>\n<meta name=\"author\" content=\"James | WuKong Math Teacher\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"James | WuKong Math Teacher\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"8 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/\",\"url\":\"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/\",\"name\":\"Volume of a Hemisphere: Formula, Examples, and How to Find It - WuKong Education\",\"isPartOf\":{\"@id\":\"https:\/\/www.wukongsch.com\/blog\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/#primaryimage\"},\"image\":{\"@id\":\"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/wp-more.wukongedu.net\/blog\/wp-content\/uploads\/2026\/09\/1-5.webp\",\"datePublished\":\"2026-09-14T08:45:43+00:00\",\"dateModified\":\"2026-09-14T08:45:45+00:00\",\"author\":{\"@id\":\"https:\/\/www.wukongsch.com\/blog\/#\/schema\/person\/577c4f1bd6e736f4ad808618c36f30c6\"},\"description\":\"Learn how to find the volume of a hemisphere using the formula V = 2\/3\u03c0r\u00b3. Explore radius and diameter examples, step-by-step solutions, common mistakes, and practice tips.\",\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/\"]}]},{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/#primaryimage\",\"url\":\"https:\/\/wp-more.wukongedu.net\/blog\/wp-content\/uploads\/2026\/09\/1-5.webp\",\"contentUrl\":\"https:\/\/wp-more.wukongedu.net\/blog\/wp-content\/uploads\/2026\/09\/1-5.webp\",\"width\":824,\"height\":431,\"caption\":\"volume of a hemisphere\"},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/www.wukongsch.com\/blog\/#website\",\"url\":\"https:\/\/www.wukongsch.com\/blog\/\",\"name\":\"WuKong Edu Blog\",\"description\":\"The latest news and comprehensive content about K-12 and Pre-K12 education for Chinese learning &amp; International Math &amp; English reading, writing learning for 3-18 students.\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/www.wukongsch.com\/blog\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"Person\",\"@id\":\"https:\/\/www.wukongsch.com\/blog\/#\/schema\/person\/577c4f1bd6e736f4ad808618c36f30c6\",\"name\":\"James | WuKong Math Teacher\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/www.wukongsch.com\/blog\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/wp-more.wukongedu.net\/blog\/wp-content\/litespeed\/avatar\/e3888295fb9b47750d9ad85a5a9bf15d.jpg?ver=1789097230\",\"contentUrl\":\"https:\/\/wp-more.wukongedu.net\/blog\/wp-content\/litespeed\/avatar\/e3888295fb9b47750d9ad85a5a9bf15d.jpg?ver=1789097230\",\"caption\":\"James | WuKong Math Teacher\"},\"description\":\"Graduated from Columbia University in the United States and has rich practical experience in mathematics competitions' teaching, including Math Kangaroo, AMC 8... He teaches students the ways to flexible thinking and quick thinking in sloving math questions, and he is good at inspiring and guiding students to think about mathematical problems and find solutions.\",\"url\":\"https:\/\/www.wukongsch.com\/blog\/author\/james\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"Volume of a Hemisphere: Formula, Examples, and How to Find It - WuKong Education","description":"Learn how to find the volume of a hemisphere using the formula V = 2\/3\u03c0r\u00b3. Explore radius and diameter examples, step-by-step solutions, common mistakes, and practice tips.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"og_locale":"en_US","og_type":"article","og_title":"Volume of a Hemisphere: Formula, Examples, and How to Find It - WuKong Education","og_description":"Learn how to find the volume of a hemisphere using the formula V = 2\/3\u03c0r\u00b3. Explore radius and diameter examples, step-by-step solutions, common mistakes, and practice tips.","og_url":"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/","og_site_name":"WuKong Education","article_published_time":"2026-09-14T08:45:43+00:00","article_modified_time":"2026-09-14T08:45:45+00:00","og_image":[{"width":824,"height":431,"url":"https:\/\/wp-more.wukongedu.net\/blog\/wp-content\/uploads\/2026\/09\/1-5.webp","type":"image\/webp"}],"author":"James | WuKong Math Teacher","twitter_card":"summary_large_image","twitter_misc":{"Written by":"James | WuKong Math Teacher","Est. reading time":"8 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/","url":"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/","name":"Volume of a Hemisphere: Formula, Examples, and How to Find It - WuKong Education","isPartOf":{"@id":"https:\/\/www.wukongsch.com\/blog\/#website"},"primaryImageOfPage":{"@id":"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/#primaryimage"},"image":{"@id":"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/#primaryimage"},"thumbnailUrl":"https:\/\/wp-more.wukongedu.net\/blog\/wp-content\/uploads\/2026\/09\/1-5.webp","datePublished":"2026-09-14T08:45:43+00:00","dateModified":"2026-09-14T08:45:45+00:00","author":{"@id":"https:\/\/www.wukongsch.com\/blog\/#\/schema\/person\/577c4f1bd6e736f4ad808618c36f30c6"},"description":"Learn how to find the volume of a hemisphere using the formula V = 2\/3\u03c0r\u00b3. Explore radius and diameter examples, step-by-step solutions, common mistakes, and practice tips.","inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/"]}]},{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/www.wukongsch.com\/blog\/volume-of-a-hemisphere-post-65348\/#primaryimage","url":"https:\/\/wp-more.wukongedu.net\/blog\/wp-content\/uploads\/2026\/09\/1-5.webp","contentUrl":"https:\/\/wp-more.wukongedu.net\/blog\/wp-content\/uploads\/2026\/09\/1-5.webp","width":824,"height":431,"caption":"volume of a hemisphere"},{"@type":"WebSite","@id":"https:\/\/www.wukongsch.com\/blog\/#website","url":"https:\/\/www.wukongsch.com\/blog\/","name":"WuKong Edu Blog","description":"The latest news and comprehensive content about K-12 and Pre-K12 education for Chinese learning &amp; International Math &amp; English reading, writing learning for 3-18 students.","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/www.wukongsch.com\/blog\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/www.wukongsch.com\/blog\/#\/schema\/person\/577c4f1bd6e736f4ad808618c36f30c6","name":"James | WuKong Math Teacher","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/www.wukongsch.com\/blog\/#\/schema\/person\/image\/","url":"https:\/\/wp-more.wukongedu.net\/blog\/wp-content\/litespeed\/avatar\/e3888295fb9b47750d9ad85a5a9bf15d.jpg?ver=1789097230","contentUrl":"https:\/\/wp-more.wukongedu.net\/blog\/wp-content\/litespeed\/avatar\/e3888295fb9b47750d9ad85a5a9bf15d.jpg?ver=1789097230","caption":"James | WuKong Math Teacher"},"description":"Graduated from Columbia University in the United States and has rich practical experience in mathematics competitions' teaching, including Math Kangaroo, AMC 8... He teaches students the ways to flexible thinking and quick thinking in sloving math questions, and he is good at inspiring and guiding students to think about mathematical problems and find solutions.","url":"https:\/\/www.wukongsch.com\/blog\/author\/james\/"}]}},"amp_enabled":false,"read_time":"3","_links":{"self":[{"href":"https:\/\/wp-more.wukongedu.net\/blog\/wp-json\/wp\/v2\/posts\/65348","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/wp-more.wukongedu.net\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/wp-more.wukongedu.net\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/wp-more.wukongedu.net\/blog\/wp-json\/wp\/v2\/users\/211806805"}],"replies":[{"embeddable":true,"href":"https:\/\/wp-more.wukongedu.net\/blog\/wp-json\/wp\/v2\/comments?post=65348"}],"version-history":[{"count":1,"href":"https:\/\/wp-more.wukongedu.net\/blog\/wp-json\/wp\/v2\/posts\/65348\/revisions"}],"predecessor-version":[{"id":65357,"href":"https:\/\/wp-more.wukongedu.net\/blog\/wp-json\/wp\/v2\/posts\/65348\/revisions\/65357"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/wp-more.wukongedu.net\/blog\/wp-json\/wp\/v2\/media\/65350"}],"wp:attachment":[{"href":"https:\/\/wp-more.wukongedu.net\/blog\/wp-json\/wp\/v2\/media?parent=65348"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/wp-more.wukongedu.net\/blog\/wp-json\/wp\/v2\/categories?post=65348"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/wp-more.wukongedu.net\/blog\/wp-json\/wp\/v2\/tags?post=65348"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}